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How can I filter a Django query with a list of values?

... FlipperPA 10k33 gold badges2525 silver badges4949 bronze badges answered Feb 16 '12 at 3:05 charlaxcharlax ...
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Read environment variables in Node.js

... | edited Dec 10 '16 at 19:24 Michał Perłakowski 63.1k2121 gold badges133133 silver badges148148 bronze badges ...
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JavaScript file upload size validation

... answered Sep 15 '10 at 13:05 T.J. CrowderT.J. Crowder 825k153153 gold badges15111511 silver badges15531553 bronze badges ...
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map function for objects (instead of arrays)

... answered Feb 11 '13 at 10:52 AmberlampsAmberlamps 29k44 gold badges3232 silver badges4646 bronze badges ...
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Index on multiple columns in Ruby on Rails

...above and stackoverflow.com/a/1449466/5157706 and stackoverflow.com/a/22816105/5157706, consider adding unique index on the database as well. – Akash Agarwal Jan 27 '18 at 6:38 ...
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Finding a substring within a list in Python [duplicate]

...ut consider this example: import timeit mylist = ['abc123'] + ['xyz123']*1000 sub = 'abc' timeit.timeit('[s for s in mylist if sub in s]', setup='from __main__ import mylist, sub', number=100000) # for me 7.949463844299316 with Python 2.7, 8.568840944994008 with Python 3.4 timeit.timeit('next((s ...
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Count number of occurences for each unique value

... answered Nov 18 '10 at 13:23 ChaseChase 59.5k1515 gold badges131131 silver badges157157 bronze badges ...
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How to filter object array based on attributes?

...thod: var newArray = homes.filter(function (el) { return el.price <= 1000 && el.sqft >= 500 && el.num_of_beds >=2 && el.num_of_baths >= 2.5; }); Live Example: var obj = { 'homes': [{ "home_id": "1", ...
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android.content.res.Resources$NotFoundException: String resource ID #0x0

... Ahmad 54.4k1717 gold badges102102 silver badges130130 bronze badges answered Nov 24 '13 at 16:38 Ken WolfKen Wolf ...
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Difference between getDefaultSharedPreferences and getSharedPreferences

... Simone 16.3k1010 gold badges6666 silver badges9696 bronze badges answered Jun 10 '11 at 17:38 copoliicopolii ...