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Access multiple elements of list knowing their index
I need to choose some elements from the given list, knowing their index. Let say I would like to create a new list, which contains element with index 1, 2, 5, from given list [-2, 1, 5, 3, 8, 5, 6]. What I did is:
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How to reload or re-render the entire page using AngularJS
...angular.js file. If you are continuing to use $routeProvider then you will now need to include angular-route.js in your HTML:
– Alvaro Joao
Feb 4 '16 at 16:02
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Split string with multiple delimiters in Python [duplicate]
...on of yours toward this problem. I think it is a great one. "If you don't know a direct answer, use combination of things you know to solve it".
– AliBZ
Jul 23 '13 at 18:04
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Debug code-first Entity Framework migration codes
... I'm just wondering if there is any way to debug the migration codes. You know, like setting breakpoints and stuff like this.
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ERROR 2003 (HY000): Can't connect to MySQL server on '127.0.0.1' (111)
...ed out that line, saved the file, and then ran service mysql restart. And now it works!
– Ryan
Jan 20 '14 at 17:59
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Problems with pip install numpy - RuntimeError: Broken toolchain: cannot link a simple C program
...talling a gem
Ruby Gem install Json fails on Mavericks and Xcode 5.1 - unknown argument: '-multiply_definedsuppress'
This is only a temporary fix, at some point the compiler options will have to be fixed
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Draw line in UIView
...extAddLineToPoint(context, 20.0f, 20.0f); //draw to this point
// and now draw the Path!
CGContextStrokePath(context);
}
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How to convert an int to a hex string?
... if the output letters are upper or lower.):
'{:x}'.format(15)
> f
And now with the new f'' format strings you can do:
f'{15:x}'
> f
To add 0 padding you can use 0>n:
f'{2034:0>4X}'
> 07F2
NOTE: the initial 'f' in f'{15:x}' is to signify a format string
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Why is division in Ruby returning an integer instead of decimal value?
... I've built a prime number generator in Ruby in order to learn the syntax, now I'm optimizing it to learn what works best. Here's the benchmark I put together: require 'base64';require 'zlib';puts Zlib.inflate(Base64.decode64("eJxlkMEOwiAQRO98hekFuGzxQEwPXvwR01ZqiYHqBk2Tln8XDlWgnDbM25nJonq9NaoD7ZTtR...
Create a string with n characters
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Hmm now that I think about it, maybe Arrays.fill:
char[] charArray = new char[length];
Arrays.fill(charArray, ' ');
String str = new String(charArray);
Of course, I assume that the fill method does the same thing as your code,...
