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Difference between a theta join, equijoin and natural join

I'm having trouble understanding relational algebra when it comes to theta joins, equijoins and natural joins. Could someone please help me better understand it? If I use the = sign on a theta join is it exactly the same as just using a natural join? ...
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Custom views with Storyboard

... UIView and the MyWidget class is the File Owner of the UIView. In the init of this widget I do a loadNibNamed . 3 Answe...
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Passing current scope to an AngularJS Service

Is it correct to pass the "current" $scope to an AngularJS service? 4 Answers 4 ...
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How to implement a secure REST API with node.js

I start planning a REST API with node.js ,express and mongodb. The API provides data for a website (public and private area) and maybe later a mobile app. The frontend will be developed with AngularJS. ...
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Why does Math.floor return a double?

... double that is "equal to a mathematical integer", but then why shouldn't it return an int ? 6 Answers ...
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How to sparsely checkout only one single file from a git repository?

How do I checkout just one file from a git repo? 21 Answers 21 ...
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Get int value from enum in C#

...t something = (int) Question.Role; The above will work for the vast majority of enums you see in the wild, as the default underlying type for an enum is int. However, as cecilphillip points out, enums can have different underlying types. If an enum is declared as a uint, long, or ulong, it should...
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PHP case-insensitive in_array function

Is it possible to do case-insensitive comparison when using the in_array function? 11 Answers ...
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What's to stop malicious code from spoofing the “Origin” header to exploit CORS?

The way I understand it, if a client-side script running on a page from foo.com wants to request data from bar.com, in the request it must specify the header Origin: http://foo.com , and bar must respond with Access-Control-Allow-Origin: http://foo.com . ...
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Creating an instance of class

... Foo (); Creates an object of type Foo in dynamic memory. foo1 points to it. Normally, you wouldn't use raw pointers in C++, but rather a smart pointer. If Foo was a POD-type, this would perform value-initialization (it doesn't apply here). /* 2 */ Foo* foo2 = new Foo; Identical to before, b...