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Python: Append item to list N times

...generation of a list of things to add via the above techniques): a = [1,2,3] b = [4,5,6] a.extend(b) # a is now [1,2,3,4,5,6] share | improve this answer | follow ...
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Stubbing a class method with Sinon.js

...cated? – loganfsmyth Jul 22 '17 at 23:57 sinon.stub(Sensor, "sample_pressure", function() {return 0}) ...
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How to determine if a number is odd in JavaScript

... 360 Use the below code: function isOdd(num) { return num % 2;} console.log("1 is " + isOdd(1...
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String comparison using '==' vs. 'strcmp()'

... 13 Answers 13 Active ...
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Replace values in list using Python [duplicate]

...n-place if you want, but it doesn't actually save time: items = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] for index, item in enumerate(items): if not (item % 2): items[index] = None Here are (Python 3.6.3) timings demonstrating the non-timesave: In [1]: %%timeit ...: items = [0, 1, 2, 3,...
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Iterating Through a Dictionary in Swift

... 360 Dictionaries in Swift (and other languages) are not ordered. When you iterate through the dict...
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Creating range in JavaScript - strange syntax

...0); //true arr[0]; //'a' Object.keys(arr); //['0', '1', '2'] arr.length; //3, implies arr[3] === undefined //we expand the array by 1 item arr.length = 4; arr[3]; //undefined arr.hasOwnProperty(3); //false Object.keys(arr); //['0', '1', '2'] We get to the inherent difference between the number of...
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Is there a Python Library that contains a list of all the ascii characters?

... If you want all printable characters: >>> string.printable '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&\'()*+,-./:;?@[\\]^_`{|}~ \t\n\r\x0b\x0c' share | imp...
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What is “point free” style (in Functional Programming)?

... answered Jun 3 '09 at 12:38 DarioDario 45k77 gold badges9090 silver badges122122 bronze badges ...
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Looping through array and removing items, without breaking for loop

...| edited Dec 8 '17 at 17:03 community wiki 4 re...