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How can I check if a method is static using reflection?
... getStaticMethods(Class<?> clazz) {
List<Method> methods = new ArrayList<Method>();
for (Method method : clazz.getMethods()) {
if (Modifier.isStatic(method.getModifiers())) {
methods.add(method);
}
}
return Collections.unmodifiableList(me...
Writing/outputting HTML strings unescaped
...ring in model or directly inline and use regular @:
@{ var myHtmlString = new HtmlString(mystring);}
@myHtmlString
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How should I use try-with-resources with JDBC?
...SELECT id, username FROM users WHERE id = ?";
List<User> users = new ArrayList<>();
try (Connection con = DriverManager.getConnection(myConnectionURL);
PreparedStatement ps = con.prepareStatement(sql)) {
ps.setInt(1, userId);
try (ResultSet rs = ps.execut...
Is there a way to keep Hudson / Jenkins configuration files in source control?
I am new to Hudson / Jenkins and was wondering if there is a way to check in Hudson's configuration files to source control.
...
Is it possible to make an ASP.NET MVC route based on a subdomain?
...
You can do it by creating a new route and adding it to the routes collection in RegisterRoutes in your global.asax. Below is a very simple example of a custom Route:
public class ExampleRoute : RouteBase
{
public override RouteData GetRouteData(H...
Changing CSS Values with Javascript
...y the above described css() function.
(function (scope) {
// Create a new stylesheet in the bottom
// of <head>, where the css rules will go
var style = document.createElement('style');
document.head.appendChild(style);
var stylesheet = style.sheet;
scope.css = functio...
Start service in Android
...t may help.
More likely, you should start the service via:
startService(new Intent(this, UpdaterServiceManager.class));
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Getting full URL of action in ASP.NET MVC [duplicate]
...quest in an action method:
var fullUrl = this.Url.Action("Edit", "Posts", new { id = 5 }, this.Request.Url.Scheme);
HtmlHelper (@Html) also has an overload of the ActionLink method that you can use in razor to create an anchor element, but it also requires the hostName and fragment parameters. So...
jQuery: How can i create a simple overlay?
...his will be your jQuery code (no UI needed). You're just going to create a new element with the ID #overlay. Creating and destroying the DIV should be all you need.
var overlay = jQuery('<div id="overlay"> </div>');
overlay.appendTo(document.body)
For performance reasons you might wan...
How to get Core Data object from specific Object ID?
...unction () {
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