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Accessing member of base class
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var tom: Animal = new Horse("Tommy the Palomino");
sam.move();
tom.move(34);
You don't need to manually assign the name to a public variable. Using public name in the constructor definition does this for you.
You don't need to call super(name) from the specialised classes.
Using this.name work...
Difference between char* and const char*?
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edited Feb 28 '18 at 23:51
Lawrence Dol
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HTTP Content-Type Header and JSON
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The Content-Type header is just used as info for your application. The browser doesn't care wh...
What does (angle brackets) mean in Java?
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3
One of the best explanations I have seen so far :) Much appreciated!.
– Suhas Chikkanna
Dec 18 '18 at...
Could not load file or assembly 'System.Web.Http 4.0.0 after update from 2012 to 2013
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edited Aug 29 '17 at 17:38
meJustAndrew
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answer...
Git reset --hard and push to remote repository
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Henrik
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answered Sep 4 '09 at 8:22
Jakub NarębskiJakub N...
Intellij IDEA, format all code in a project
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answered Mar 12 '11 at 16:36
FriesgaardFriesgaard
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What is a servicebus and when do I need one?
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3 Answers
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How do I write LINQ's .Skip(1000).Take(100) in pure SQL?
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edited Feb 19 '13 at 16:48
Drew Miller
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answered Nov 16 '...
How to get the function name from within that function?
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answered Mar 30 '13 at 2:59
Vlad A. IonescuVlad A. Ionescu
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