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Real life example, when to use OUTER / CROSS APPLY in SQL
... reference the outer table, where INNER JOIN cannot do this(throws compile error). When finding the last two dates, joining is done inside CROSS APPLY ie, WHERE M.ID=D.ID.
2. When we need INNER JOIN functionality using functions.
CROSS APPLY can be used as a replacement with INNER JOIN when we ne...
How to get “wc -l” to print just the number of lines without file name?
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I get syntax errors with this (Ubuntu 14.04). I think there is a problem with the filename.
– MERose
Jul 7 '15 at 23:34
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How can I pass arguments to a batch file?
...like "&"^&, as it's not possible to access %1 without producing an error.
set var=%1
set "var=%1"
set var=%~1
set "var=%~1"
The lines expand to
set var="&"&
set "var="&"&"
set var="&"&
set "var="&"&"
And each line fails, as one of the & is ou...
Linux日志管理Rsyslog入门 - C/C++ - 清泛网移动版 - 专注C/C++及内核技术
...稍后有 Gearman 把任务分发给相应的 Worker 来处理。
友情提示：如果主配置文件太臃肿的话，可以考虑使用子配置文件：
# Include all config files in /etc/rsyslog.d/
$IncludeConfig /etc/rsyslog.d/*.conf
本文可以看作是Rsyslog入门指引，深入介...
Pro JavaScript programmer interview questions (with answers) [closed]
... The sum function should be resilient to non number types without throwing errors. In addition it should be able to handle numbers as strings for extra credit.
– Abadaba
Dec 19 '12 at 6:25
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How to only get file name with Linux 'find'?
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kenorb
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answered Mar 28 '11 at 8:00
SiegeXSiegeX
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Horizontal ListView in Android?
...on code of android 4.2.2 ListView. I must say that it doesn't have all the errors which previous version had and works great!
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How can I make PHP display the error instead of giving me 500 Internal Server Error [duplicate]
This has never happened before. Usually it displays the error, but now it just gives me a 500 internal server error. Of course before, when it displayed the error, it was different servers. Now I'm on a new server (I have full root, so if I need to configure it somewhere in the php.ini, I can.) Or p...
App Inventor 2 中文网 · 项目指南
... 5000 + 次 连接测试 20000 + 次 累计在线时长 50000 + 时 文档翻译进...
Are strongly-typed functions as parameters possible in TypeScript?
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console.log(result);
}
foo.save(stringCallback); //--will be showing error
foo.save(numberCallback);
Without function type by using plain property syntax it would be:
class Foo {
save(callback: (n: number) => void) : void {
callback(42);
}
}
var foo = new Foo();
...