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Download a file by jQuery.Ajax

...ct that to get more StackOverFlow credit your answer here should contain a bit more detail. Specifically on how you solved the problem. – AnthonyVO Aug 7 '12 at 21:58 14 ...
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In-place type conversion of a NumPy array

...) that want conversion between dtype of different byte-size (e.g. 32 to 16 bits): This method fails because y.size <> x.size. Logical once you think about it :-( – Juh_ Jun 12 '12 at 9:17 ...
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Using pip behind a proxy with CNTLM

... To setup CNTLM for windows, follow this article. For Ubuntu, read my blog post. Edit: Basically, to use CNTLM in any platform, you need to setup your username and hashed password, before using http://127.0.0.1:3128 as a proxy to your parent ...
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Why does base64 encoding require padding if the input length is not divisible by 3?

... On a related note, here's a base converter for arbitrary base conversion I created for you. Enjoy! https://convert.zamicol.com/ What are Padding Characters? Padding characters help satisfy length requirements and carry no meaning. Decimal Example of Padding: Given the...
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Tick symbol in HTML/XHTML

...lues, which don't always have glyphs for all the code points. Try the following characters: ☐ (0x2610 in Unicode hexadecimal [HTML decimal: ☐]): an empty (unchecked) checkbox ☑ (0x2611 [HTML decimal: ☑]): the checked version of the previous checkbox ✓ (0x2713 [HTML decima...
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Why does changing 0.1f to 0 slow down performance by 10x?

Why does this bit of code, 5 Answers 5 ...
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Compression/Decompression string with C#

... be disposed before calling ToArray() on the output stream. I ignored that bit, but it makes a difference! – Wet Noodles Jan 23 '14 at 19:41 1 ...
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Optional Parameters with C++ Macros

...s little as possible, I found that debugging via trace output gets quite a bit easier with things like __FILE__ and __LINE__ and such... – Christian Severin Mar 25 '15 at 14:21 ...
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Why does GCC generate such radically different assembly for nearly the same C code?

...vial holds. Adding and xoring by 0x80000000 is the same. It flips the sign bit. Therefore x + (y ^ x) = y also holds when x = 0x80000000. Therefore, x + (y ^ x) reduces to y. And the code simplifies to this: int fast_trunc_one(int i) { int mantissa, exponent, sign, r; mantissa = (i & 0...
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(-2147483648> 0) returns true in C++?

-2147483648 is the smallest integer for integer type with 32 bits, but it seems that it will overflow in the if(...) sentence: ...