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Download a file by jQuery.Ajax
...ct that to get more StackOverFlow credit your answer here should contain a bit more detail. Specifically on how you solved the problem.
– AnthonyVO
Aug 7 '12 at 21:58
14
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In-place type conversion of a NumPy array
...) that want conversion between dtype of different byte-size (e.g. 32 to 16 bits): This method fails because y.size <> x.size. Logical once you think about it :-(
– Juh_
Jun 12 '12 at 9:17
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Using pip behind a proxy with CNTLM
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To setup CNTLM for windows, follow this article. For Ubuntu, read my blog post.
Edit:
Basically, to use CNTLM in any platform, you need to setup your username and hashed password, before using http://127.0.0.1:3128 as a proxy to your parent ...
Why does base64 encoding require padding if the input length is not divisible by 3?
...
On a related note, here's a base converter for arbitrary base conversion I created for you. Enjoy!
https://convert.zamicol.com/
What are Padding Characters?
Padding characters help satisfy length requirements and carry no meaning.
Decimal Example of Padding:
Given the...
Tick symbol in HTML/XHTML
...lues, which don't always have glyphs for all the code points.
Try the following characters:
☐ (0x2610 in Unicode hexadecimal [HTML decimal: &#9744;]): an empty (unchecked) checkbox
☑ (0x2611 [HTML decimal: &#9745;]): the checked version of the previous checkbox
✓ (0x2713 [HTML decima...
Why does changing 0.1f to 0 slow down performance by 10x?
Why does this bit of code,
5 Answers
5
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Compression/Decompression string with C#
... be disposed before calling ToArray() on the output stream. I ignored that bit, but it makes a difference!
– Wet Noodles
Jan 23 '14 at 19:41
1
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Optional Parameters with C++ Macros
...s little as possible, I found that debugging via trace output gets quite a bit easier with things like __FILE__ and __LINE__ and such...
– Christian Severin
Mar 25 '15 at 14:21
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Why does GCC generate such radically different assembly for nearly the same C code?
...vial holds.
Adding and xoring by 0x80000000 is the same. It flips the sign bit. Therefore x + (y ^ x) = y also holds when x = 0x80000000.
Therefore, x + (y ^ x) reduces to y. And the code simplifies to this:
int fast_trunc_one(int i) {
int mantissa, exponent, sign, r;
mantissa = (i & 0...
(-2147483648> 0) returns true in C++?
-2147483648 is the smallest integer for integer type with 32 bits, but it seems that it will overflow in the if(...) sentence:
...
