大约有 800 项符合查询结果(耗时:0.0176秒) [XML]

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Check if something is (not) in a list in Python

... 0.613 ns per loop (mean ± std. dev. of 7 runs, 10000000 loops each) 178 µs ± 5.01 µs per loop (mean ± std. dev. of 7 runs, 10000 loops each) If you want to do more than just check whether an item is in a list, there are options: list.index can be used to retrieve the index of an item. If t...
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.gitignore is ignored by Git

...red Mar 19 '14 at 23:40 H AßdøµH Aßdøµ 2,31033 gold badges1414 silver badges2424 bronze badges ...
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Python string class like StringBuilder in C#?

...]: %%timeit ...: ''.join(values) ...: 100000 loops, best of 3: 7.37 µs per loop In [3]: %%timeit ...: result = '' ...: for value in values: ...: result += value ...: 10000 loops, best of 3: 82.8 µs per loop In [4]: import io In [5]: %%timeit ...: writer = io.StringIO(...
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Replace values in list using Python [duplicate]

....: if not (item % 2): ...: items[index] = None ...: 1.06 µs ± 33.7 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each) In [2]: %%timeit ...: items = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] ...: new_items = [x if x % 2 else None for x in items] ...: 891 ns ± 13.6 n...
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How to add an extra column to a NumPy array

...b = np.hstack((a, np.zeros((a.shape[0], 1)))) 100000 loops, best of 3: 7.5 µs per loop In [4]: %timeit b = np.zeros((a.shape[0], a.shape[1]+1)); b[:,:-1] = a 100000 loops, best of 3: 2.17 µs per loop In [5]: %timeit b = np.insert(a, 3, values=0, axis=1) 100000 loops, best of 3: 10.2 µs per loop...
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How do I select elements of an array given condition?

...that an intermediate result is being cached. 100000 loops, best of 3: 1.15 µs per loop >>> %timeit np.logical_and(a < b, b < c) The slowest run took 32.59 times longer than the fastest. This could mean that an intermediate result is being cached. 1000000 loops, best of 3: 1.17 µs p...
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Numpy first occurrence of value greater than existing value

...timeit np.nonzero(aa>N/2)[0][0] # Output 100000 loops, best of 3: 5.97 µs per loop 10000 loops, best of 3: 46.3 µs per loop 10000 loops, best of 3: 154 µs per loop 10000 loops, best of 3: 154 µs per loop share ...
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Set breakpoint in C or C++ code programmatically for gdb on Linux

... answered Dec 1 '10 at 16:22 Håvard SHåvard S 20.4k55 gold badges5555 silver badges6767 bronze badges ...
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Getting error while sending email through Gmail SMTP - “Please log in via your web browser and then

...wered Sep 9 '15 at 0:55 H AßdøµH Aßdøµ 2,31033 gold badges1414 silver badges2424 bronze badges ...
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Extract first item of each sublist

...t numpy-way, transforming the array: %timeit list(np.array(lst).T[0]) 4.9 µs ± 163 ns per loop (mean ± std. dev. of 7 runs, 100000 loops each) Fully native using list comprehension (as explained by @alecxe): %timeit [item[0] for item in lst] 379 ns ± 23.1 ns per loop (mean ± std. dev. of 7 ...